COMEDK · Maths · 12. Circle
Find the centre and radius of the circle given by the equation \(2 x^{2}+2 y^{2}+3 x+4 y+\dfrac{9}{8}=0\).
- A 1
- B \(-1\)
- C 2
- D \(-2\)
Answer & Solution
Correct Answer
(A) 1
Step-by-step Solution
Detailed explanation
The given equation of the circle is \(2x^{2} + 2y^{2} + 3x + 4y + \dfrac{9}{8} = 0\). Dividing the entire equation by \(2\), we get \(x^{2} + y^{2} + \dfrac{3}{2}x + 2y + \dfrac{9}{16} = 0\). Comparing this with the standard form \(x^{2} + y^{2} + 2gx + 2fy + c = 0\), we…
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