COMEDK · Maths · 27. Application of Derivatives
Find the approximate value of function \(f(x)=x^3-5 x+10\) at \(x=3.001\).
- A 31.023
- B 22.007
- C 31.23
- D 22.07
Answer & Solution
Correct Answer
(D) 22.07
Step-by-step Solution
Detailed explanation
We can write 3.001 as \(x=3\) and \(\Delta x=0.001\) and use the relation \(\begin{aligned} & f(x+\Delta x) \approx f(x)+\Delta x f^{\prime}(x) \\ & f^{\prime}(x)=3 x^2-5 \end{aligned}\) Now,…
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