COMEDK · Maths · 7. Binomial Theorem
Evaluate the value of \((1.02)^8\) using binomial theorem up to two decimal places.
- A 1.71
- B 1.17
- C 1.18
- D 1.81
Answer & Solution
Correct Answer
(B) 1.17
Step-by-step Solution
Detailed explanation
Using the binomial theorem, \((1 + x)^{n} = 1 + nx + \dfrac{n(n-1)}{2!}x^2 + \dfrac{n(n-1)(n-2)}{3!}x^3 + \dots\) Here, \(x = 0.02\) and \(n = 8\). \((1 + 0.02)^8 = 1 + 8(0.02) + \dfrac{8 \times 7}{2}(0.02)^2 + \dfrac{8 \times 7 \times 6}{6}(0.02)^3 + \dots\) Calculating the…
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