COMEDK · Maths · 10. Straight Lines
Distance between \(8x + 15y - 20 = 0\) and \(8x + 15y + 14 = 0\) is:
- A \(\dfrac{4}{7}\) units
- B \(2\) units
- C \(\dfrac{10}{17}\) units
- D \(34\) units
Answer & Solution
Correct Answer
(B) \(2\) units
Step-by-step Solution
Detailed explanation
The given parallel lines are \(8x + 15y - 20 = 0\) and \(8x + 15y + 14 = 0\). The distance between two parallel lines \(Ax + By + C_1 = 0\) and \(Ax + By + C_2 = 0\) is given by \(d = \dfrac{|C_1 - C_2|}{\sqrt{A^2 + B^2}}\). Substituting \(A = 8\), \(B = 15\), \(C_1 = -20\), and…
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