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COMEDK · Maths · 34. Three Dimensional Geometry

Determine the plane through the intersection of the planes \(x+2 y+3 z-4=0\) and
\(2 x+y-z+5=0\) and perpendicular to the plane
\(5 x+3 y+6 z+8=0\)

  1. A \(-51 x-15 y-50 z-173=0\)
  2. B \(51 x+15 y-50 z+173=0\)
  3. C \(51 x-15 y+50 z-173=0\)
  4. D \(51 x+50 y+15 z+173=0\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(51 x+15 y-50 z+173=0\)

Step-by-step Solution

Detailed explanation

Equation of plane through the intersection of planes \(x+2 y+3 z-4=0\) and \(2 x+y-z+5=0\) is \((x+2 y+3 z-4)+k(2 x+y-z+5)=0\) or \((1+2 k) x+(2+k) y+(3-k) z+(5 k-4)=0 \quad \text{...(i)}\) D.R.' \(s\) of normal of plane (i) are \[ = \] Given,…