COMEDK · Maths · 22. Determinants
\(\left|\begin{array}{ccc}1 & 1 & 1 \\ a & b & c \\ a^{2}-b c & b^{2}-c a & c^{2}-a b\end{array}\right|\) is equal to
- A 0
- B 1
- C \(a b c\)
- D \((a-b)(b-c)(c-a)\)
Answer & Solution
Correct Answer
(A) 0
Step-by-step Solution
Detailed explanation
Let \(\Delta=\left|\begin{array}{ccc}1 & 1 & 1 \\ a & b & c \\ a^{2}-b c & b^{2}-c a & c^{2}-a b\end{array}\right|\) On applying \(C_{3} \rightarrow C_{3}-C_{2}\) and \(C_{2} \rightarrow C_{2}-C_{1}\), we get…
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