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COMEDK · Maths · 36. Probability

An urn contains 9 balls, 2 of which are white, 3 blue and 4 black. 3 balls are drawn at random from the urn. The chance that 2 balls will be of the same colour and the third of a different colour is

  1. A \(\frac{45}{84}\)
  2. B \(\frac{55}{84}\)
  3. C \(\frac{35}{84}\)
  4. D \(\frac{25}{84}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{55}{84}\)

Step-by-step Solution

Detailed explanation

Let \(E_{1}, E_{2}\) and \(E_{3}\) be the the events such that drawn ball is white, blue and black respectively. The required probability…
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