COMEDK · Maths · 28. Indefinite Integration
An unbiased die is tossed twice. What is the probability of getting a 4,5 or 6 on the first toss and a 1,2,3 or 4 on the second toss?
- A \(\dfrac{3}{4}\)
- B \(\dfrac{1}{3}\)
- C \(\dfrac{5}{6}\)
- D \(\dfrac{2}{3}\)
Answer & Solution
Correct Answer
(B) \(\dfrac{1}{3}\)
Step-by-step Solution
Detailed explanation
The sample space for tossing an unbiased die twice consists of \(6 \times 6 = 36\) equally likely outcomes. Let \(A\) be the event of getting a 4, 5, or 6 on the first toss. The number of favorable outcomes for the first toss is 3, so \(P(A) = \dfrac{3}{6} = \dfrac{1}{2}\). Let…
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