COMEDK · Maths · 27. Application of Derivatives
A stone is thrown vertically upwards and the height \(x f\) t. reached by the stone in \(t\) sec is given by \(x=80 t-16 t^{2}\). The stone reaches the maximum height in
- A \(2 \mathrm{sec}\)
- B \(2.5 \mathrm{sec}\)
- C \(3 \mathrm{sec}\)
- D \(1.5 \mathrm{sec}\)
Answer & Solution
Correct Answer
(B) \(2.5 \mathrm{sec}\)
Step-by-step Solution
Detailed explanation
We have, \[ \begin{aligned} x &=80 t-16 t^{2} \\ \Rightarrow \quad \frac{d x}{d i} &=80-32 t \end{aligned} \] For maximum value of \(x\), \[ \begin{aligned} \frac{d x}{d t} &=0 \\ \Rightarrow 80-32 t &=0 \Rightarrow t=\frac{80}{32}=2.5 \end{aligned} \] Again,…
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