COMEDK · Maths · 27. Application of Derivatives
A spherical balloon is being inflated at the rate of \(35 \mathrm{~cm} / \mathrm{min}\). When its radius is \(7 \mathrm{~cm}\), its surface area increases at the rate of
- A \(10 \mathrm{~cm}^{2} / \mathrm{min}\)
- B \(15 \mathrm{~cm}^{2} / \mathrm{min}\)
- C \(20 \mathrm{~cm}^{2} / \mathrm{min}\)
- D \(25 \mathrm{~cm}^{2} / \mathrm{min}\)
Answer & Solution
Correct Answer
(A) \(10 \mathrm{~cm}^{2} / \mathrm{min}\)
Step-by-step Solution
Detailed explanation
Given, \(\frac{d V}{d t}=35\) where, \(V\) is volume of spherical balloon.…
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