COMEDK · Maths · 36. Probability
A pot contains 5 red and 2 green balls. A ball is drawn at random from this pot. If a drawn ball is green, then a red ball is added to the pot. If a drawn ball is red, then a green ball is added to the pot, while the original ball drawn is not replaced in the pot. Now a second ball is drawn at random from the pot, what is the probability that the second ball drawn is a red ball?
- A \(\dfrac{27}{49}\)
- B \(\dfrac{3}{7}\)
- C \(\dfrac{32}{49}\)
- D \(\dfrac{12}{49}\)
Answer & Solution
Correct Answer
(C) \(\dfrac{32}{49}\)
Step-by-step Solution
Detailed explanation
Let \(R_1\) and \(G_1\) be the events that the first ball drawn is red and green, respectively. Initially, the pot contains 5 red and 2 green balls, total 7 balls. Probability of drawing a red ball first: \(P(R_1) = \dfrac{5}{7}\). Probability of drawing a green ball first:…
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