COMEDK · Maths · 36. Probability
A number \(\mathrm{n}\) is chosen at random from \(s=\{1,2,3, \ldots, 50\}\). Let \(\mathrm{A}=\{n \in s: n\) is a square \(\}\), \(\mathrm{B}=\{n \in s: n\) is a prime \(\}\) and \(\mathrm{C}=\{n \in s: n\) is a square \(\}\). Then, correct order of their probabilities is
- A \(p(A) < p(B) < p(C)\)
- B \(p(A)>p(B)>p(C)\)
- C \(p(\mathrm{~B}) < p(A) < p(C)\)
- D \(p(A)>p(c)>p(B)\)
Answer & Solution
Correct Answer
(B) \(p(A)>p(B)>p(C)\)
Step-by-step Solution
Detailed explanation
Given, \(S=\{1,2,3 \ldots, 50\}\) \(\begin{aligned} A & +\left\{n \in S: n+\frac{50}{n}>27\right\} \\ & =\left\{n \in S: n^2-27 n+50>0\right\} \\ & =\{n \in S:(n-25)(n-2)>0\} \\ & =\{n \in S: n 25\} \\ & =\{1,26,27,28, \ldots, 50\} \end{aligned}\)…
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