COMEDK · Maths · 36. Probability
A number n is chosen at random from \(s = \{1, 2, 3, \dots, 50\}\). Let A = {\(n \in s : n \text{ is a prime}\)}, B = {\(n \in s : n \text{ is a square}\)} and C = {\(n \in s : n \text{ is a cube}\)}. Then, correct order of their probabilities is
- A \(p(\mathrm{~B}) < p(\mathrm{~A}) < p(C)\)
- B \(p(A) > p(B) > p(C)\)
- C \(p(A) > p(c) > p(B)\)
- D \(p(A) < p(B) < p(C)\)
Answer & Solution
Correct Answer
(B) \(p(A) > p(B) > p(C)\)
Step-by-step Solution
Detailed explanation
Primes up to 50: 2,3,5,7,11,13,17,19,23,29,31,37,41,43,47 \(\Rightarrow\) \(n(A) = 15\), \(p(A) = \dfrac{15}{50}\) Perfect squares up to 50: 1,4,9,16,25,36,49 \(\Rightarrow\) \(n(B) = 7\), \(p(B) = \dfrac{7}{50}\) Perfect cubes up to 50: 1,8,27 \(\Rightarrow\) \(n(C) = 3\),…
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