COMEDK · Maths · 36. Probability
A number \(n\) is choosen at random from \(S=\{1,2\), \(3, \ldots, 100\}\). Let \(A=\{n \in S: n\) is a perfect square \(\}, B=\{n \in S: n\) is odd number \(\}\) and \(C=\{n \in S: n\) is a even prime number \(\}\) then, correct order of their probability is
- A \(P(A) \lt P(B) \lt P(C)\)
- B \(P(A) \gt P(B) \gt P(C)\)
- C \(P(B) \gt P(A) \gt P(C)\)
- D \(P(A) \gt P(C) \lt P(B)\)
Answer & Solution
Correct Answer
(C) \(P(B) \gt P(A) \gt P(C)\)
Step-by-step Solution
Detailed explanation
Total number of outcomes \(=100\) Total number of perfect square \(=10\) Total odd number \(=50\) Total number of even prime number \(=1\)…
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