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COMEDK · Maths · 36. Probability

A number \(n\) is choosen at random from \(S=\{1,2\), \(3, \ldots, 100\}\). Let \(A=\{n \in S: n\) is a perfect square \(\}, B=\{n \in S: n\) is odd number \(\}\) and \(C=\{n \in S: n\) is a even prime number \(\}\) then, correct order of their probability is

  1. A \(P(A) \lt P(B) \lt P(C)\)
  2. B \(P(A) \gt P(B) \gt P(C)\)
  3. C \(P(B) \gt P(A) \gt P(C)\)
  4. D \(P(A) \gt P(C) \lt P(B)\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(P(B) \gt P(A) \gt P(C)\)

Step-by-step Solution

Detailed explanation

Total number of outcomes \(=100\) Total number of perfect square \(=10\) Total odd number \(=50\) Total number of even prime number \(=1\)…