COMEDK · Maths · 34. Three Dimensional Geometry
A line \(L_1\) passing through the point A with position vector \(\vec{a}=4 \hat{\imath}+2 \hat{\jmath}+2 \hat{k}\) is parallel to the vector \(\vec{b}=2 \hat{\imath}+3 \hat{\jmath}+6 \hat{k}\). The length of the perpendicular drawn from a point P with position vector \(\vec{p}=\hat{\imath}+2 \hat{\jmath}+3 \hat{k}\) to \(L_1\) is
- A \(\sqrt{10}\)
- B \(\sqrt{15}\)
- C \(0\)
- D \(2 \sqrt{3}\)
Answer & Solution
Correct Answer
(A) \(\sqrt{10}\)
Step-by-step Solution
Detailed explanation
The line \(L_1\) passes through point \(A\) with position vector \(\vec{a} = 4\hat{i} + 2\hat{j} + 2\hat{k}\) and is parallel to the vector \(\vec{b} = 2\hat{i} + 3\hat{j} + 6\hat{k}\). The position vector of point \(P\) is \(\vec{p} = \hat{i} + 2\hat{j} + 3\hat{k}\). The vector…
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