COMEDK · Maths · 33. Vector Algebra
\((\mathbf{a} \cdot \hat{\mathbf{i}}) \hat{\mathbf{i}}+(\mathbf{a} \cdot \hat{\mathbf{j}}) \hat{\mathbf{j}}+(\mathbf{a} \cdot \hat{\mathbf{k}}) \hat{\mathbf{k}}\) is equal to
- A \(a\)
- B \(2 a\)
- C \(3 \mathbf{a}\)
- D \(0\)
Answer & Solution
Correct Answer
(A) \(a\)
Step-by-step Solution
Detailed explanation
Let \(\mathbf{a}=x \hat{\mathbf{i}}+y \hat{\mathbf{j}}+z \hat{\mathbf{k}}\), then \((\mathbf{a} \cdot \hat{\mathbf{i}})+(a \cdot \hat{\mathbf{j}}) \hat{\mathbf{j}}+(\mathbf{a} \cdot \hat{\mathbf{k}}) \hat{\mathbf{k}}\)…
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