COMEDK · Maths · 36. Probability
A die is thrown twice and the sum of numbers appearing is observed to be 8 . What is the conditional probability that the number 5 has appeared atleast once?
- A \(\dfrac{1}{18}\)
- B \(\dfrac{1}{3}\)
- C \(\dfrac{2}{5}\)
- D \(\dfrac{5}{36}\)
Answer & Solution
Correct Answer
(C) \(\dfrac{2}{5}\)
Step-by-step Solution
Detailed explanation
Let \(S\) be the sample space of throwing a die twice. The total number of outcomes is \(6 \times 6 = 36\). Let \(A\) be the event that the sum of the numbers appearing is 8. The possible outcomes for \(A\) are \((2, 6), (3, 5), (4, 4), (5, 3), (6, 2)\). Thus, \(n(A) = 5\). Let…
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