COMEDK · Maths · 27. Application of Derivatives
A circular sector of perimeter \(60 \mathrm{~m}\) with maximum area is to be constructed, The radius of the circular arc in metre must be
- A 10
- B 15
- C 5
- D 20
Answer & Solution
Correct Answer
(B) 15
Step-by-step Solution
Detailed explanation
Perimeter of sector \(=2 r+r \theta\) \(\Rightarrow \quad 60=2 r+r \theta\) (given) \(\Rightarrow \quad \theta=\frac{60-2 r}{r}\) Now, area of sector, \((A)=\frac{\pi r^{2} \theta}{360^{\circ}}=\frac{\pi r^{2}(60-2 r)}{360 r}\)…
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