COMEDK · Maths · 19. Properties of Triangles
\(A B C\) is a triangle with \(\angle A=30^{\circ}\) and \(B C=10 \mathrm{~cm}\). The area of the circum circle of the triangle is
- A \(5 \mathrm{sq} \mathrm{cm}\)
- B \(100 \pi \mathrm{sq} \mathrm{cm}\)
- C \(\frac{100 \pi}{3} \mathrm{sq} \mathrm{cm}\)
- D \(25 \mathrm{sq} \mathrm{cm}\)
Answer & Solution
Correct Answer
(B) \(100 \pi \mathrm{sq} \mathrm{cm}\)
Step-by-step Solution
Detailed explanation
\[ \bar{Z}=-1-i \] We know that, \(\angle B O C=2 \angle B A C=2 \times 30^{\circ}=60^{\circ}\) Since, \(O B=O C\) \(\therefore \angle O B C=\angle O C B=\frac{1}{2}\left(180^{\circ}-\angle B O C\right)=60^{\circ}\) So, \(\triangle B O C\) is an equilateral triangle.…
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