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COMEDK · Maths · 36. Probability

A and B are two independent events. The probability of their simultaneous occurrence is \(\dfrac{1}{8}\) and the probability that neither of them occurs is \(\dfrac{3}{8}\). Then their individual probabilities are

  1. A \(\dfrac{3}{8} \text { and } \dfrac{1}{8}\)
  2. B \(\dfrac{5}{8} \text { and } \dfrac{1}{4}\)
  3. C \(\dfrac{3}{4} \text { and } \dfrac{1}{2}\)
  4. D \(\dfrac{1}{2} \text { and } \dfrac{1}{4}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\dfrac{1}{2} \text { and } \dfrac{1}{4}\)

Step-by-step Solution

Detailed explanation

Let \(P(A) = x\) and \(P(B) = y\). Since \(A\) and \(B\) are independent events, \(P(A \cap B) = P(A)P(B) = xy = \dfrac{1}{8}\). The probability that neither occurs is \(P(A^{c} \cap B^{c}) = P(A^{c})P(B^{c}) = (1-x)(1-y) = \dfrac{3}{8}\). Expanding the second equation:…