COMEDK · Maths · 21. Matrices
\(A\) and \(B\) are invertible matrices of the same order such that \(\left|(A B)^{-1}\right|=8\) if \(|A|=2\) then \(|B|\) is
- A \(\dfrac{1}{16}\)
- B 6
- C 4
- D 16
Answer & Solution
Correct Answer
(A) \(\dfrac{1}{16}\)
Step-by-step Solution
Detailed explanation
Given that \(A\) and \(B\) are invertible matrices of the same order, we have the property \(|(AB)^{-1}| = \dfrac{1}{|AB|}\). Since \(|AB| = |A| |B|\), we can write \(|(AB)^{-1}| = \dfrac{1}{|A| |B|}\). Given \(|(AB)^{-1}| = 8\) and \(|A| = 2\), we substitute these values into…
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