COMEDK · Maths · 28. Indefinite Integration
\(\int \dfrac{2 x}{\left(x^2+1\right)\left(x^2+2\right)^2} d x=\)
- A \(\log \left|x^2+1\right|+\log \left|x^2+2\right|+\dfrac{1}{x^2+2}+c\)
- B \(\log \left|x^2+1\right|-\log \left|x^2+2\right|+\dfrac{1}{x+1}+c\)
- C \(\log \left|\dfrac{x^2+1}{x^2+2}\right|+\tan ^{-1} x+c\)
- D \(\log \left|\dfrac{x^2+1}{x^2+2}\right|+\dfrac{1}{x^2+2}+c\)
Answer & Solution
Correct Answer
(D) \(\log \left|\dfrac{x^2+1}{x^2+2}\right|+\dfrac{1}{x^2+2}+c\)
Step-by-step Solution
Detailed explanation
Let \(I = \int \dfrac{2x}{(x^2+1)(x^2+2)^2} dx\). Substitute \(t = x^2\), then \(dt = 2x dx\). The integral becomes \(I = \int \dfrac{dt}{(t+1)(t+2)^2}\). Using partial fractions, let \(\dfrac{1}{(t+1)(t+2)^2} = \dfrac{A}{t+1} + \dfrac{B}{t+2} + \dfrac{C}{(t+2)^2}\). Multiplying…
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