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COMEDK · Maths · 28. Indefinite Integration

\(\int \dfrac{2 x}{\sqrt{1-x^2-x^4}} d x=\sin ^{-1}[f(x)]+c\) then \(f(x)=\)

  1. A \(\dfrac{2 x^2}{\sqrt{3}}\)
  2. B \(\dfrac{2 x^2-1}{\sqrt{3}}\)
  3. C \(\dfrac{2 x^2}{\sqrt{5}}\)
  4. D \(\dfrac{2 x^2+1}{\sqrt{5}}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\dfrac{2 x^2+1}{\sqrt{5}}\)

Step-by-step Solution

Detailed explanation

Let \(I = \int \dfrac{2x}{\sqrt{1 - x^2 - x^4}} dx\). Substitute \(t = x^2\), so \(dt = 2x dx\). The integral becomes \(I = \int \dfrac{dt}{\sqrt{1 - t - t^2}}\). Complete the square in the denominator:…