COMEDK · Maths · 7. Binomial Theorem
\(\left(2^{4 n}-1\right)\) is divisible by
- A 8
- B 7
- C 15
- D 16
Answer & Solution
Correct Answer
(C) 15
Step-by-step Solution
Detailed explanation
We have, \(2^{4 n}-1=16^n-1\) \(\therefore a^n-1\) is divisible by \(a-1\) \(\Rightarrow 16^n-1\) is divisible by \(16-1=15\)
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