COMEDK · Maths · 8. Trigonometric Ratios & Identities
\(\sin ^{2} 175^{\circ}+\sin ^{2} 725^{\circ}\) is equal to
- A \(\tan ^{2} 45^{\circ}\)
- B \(\cos ^{2} 90^{\circ}\)
- C \(\sin ^{2} 45^{\circ}\)
- D \(\cos ^{2} 30^{\circ}\)
Answer & Solution
Correct Answer
(A) \(\tan ^{2} 45^{\circ}\)
Step-by-step Solution
Detailed explanation
We have, \(\quad \sin ^{2} 17.5^{\circ}+\sin ^{2} 72.5^{\circ}=\sin ^{2} 17.5^{\circ}+\cos ^{2}\left(90^{\circ}-72.5^{\circ}\right)\) \(=\sin ^{2} 175^{\circ}+\cos ^{2} 17.5^{\circ}=1=\tan ^{2} 45^{\circ}\)
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