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COMEDK · Maths · 28. Indefinite Integration

\(\int \dfrac{1}{\sqrt{9+8 x-x^2}} d x=\varphi(x)+c\) then \(\varphi(x)=\)

  1. A \(\dfrac{1}{10} \log \left|\dfrac{4-x}{4+x}\right|\)
  2. B \(\sin ^{-1}\left(\dfrac{x-4}{5}\right)\)
  3. C \(\log \left|\dfrac{4-x}{4+x}\right|\)
  4. D \(\dfrac{1}{5} \sin ^{-1}\left(\dfrac{x-4}{5}\right)\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\sin ^{-1}\left(\dfrac{x-4}{5}\right)\)

Step-by-step Solution

Detailed explanation

The integral is given by \(I = \int \dfrac{1}{\sqrt{9+8x-x^2}} dx\). Complete the square for the quadratic expression inside the square root: \(9 + 8x - x^2 = 9 - (x^2 - 8x) = 9 - (x^2 - 8x + 16 - 16) = 9 - ((x-4)^2 - 16) = 9 + 16 - (x-4)^2 = 25 - (x-4)^2\). Substitute this into…