COMEDK · Maths · 30. Definite Integration
\(\int_0^{\pi/2} \dfrac{3\sin x + 4\cos x}{\sin x + \cos x}\, dx =\)
- A \(\dfrac{7\pi}{2}\)
- B \(\dfrac{\pi}{4}\)
- C \(\dfrac{7\pi}{4}\)
- D \(7\pi\)
Answer & Solution
Correct Answer
(C) \(\dfrac{7\pi}{4}\)
Step-by-step Solution
Detailed explanation
Let \(I = \int_0^{\pi/2} \dfrac{3\sin x + 4\cos x}{\sin x + \cos x}\, dx\) Using the definite integral property \(\int_0^a f(x)\, dx = \int_0^a f(a-x)\, dx\), we get: \(I = \int_0^{\pi/2} \dfrac{3\sin(\pi/2 - x) + 4\cos(\pi/2 - x)}{\sin(\pi/2 - x) + \cos(\pi/2 - x)}\, dx\)…
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