COMEDK · Chemistry · 19. Chemical Kinetics
\(\mathrm{X} \rightarrow 2 \mathrm{Y}\) is a first order reaction where \(1.0 \mathrm{~mol} / \mathrm{L}\) of the reactant yields \(0.4 \mathrm{~mol} / \mathrm{L}\) of Y in 200 minutes. Calculate the half-life period of the reaction in minutes.
- A \(203.69\)
- B \(621.5\)
- C \(271.34\)
- D \(151.24\)
Answer & Solution
Correct Answer
(B) \(621.5\)
Step-by-step Solution
Detailed explanation
The reaction is \(\mathrm{X} \rightarrow 2 \mathrm{Y}\). Let the initial concentration of \(\mathrm{X}\) be \([A]_0 = 1.0 \text{ mol/L}\). At time \(t = 200 \text{ minutes}\), the concentration of \(\mathrm{Y}\) formed is \(0.4 \text{ mol/L}\). From the stoichiometry, the amount…
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