COMEDK · Chemistry · 27. Aldehydes and Ketones
Which one of the following reactions does not give the correct combination of reactants and the major products formed in the reaction?
- A \(\mathrm{CH}_3 \mathrm{CHO}+2 \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}(\) dry HCl gas \() \leftrightharpoons \mathrm{CH}_3-\mathrm{CH}-\left(\mathrm{OC}_2 \mathrm{H}_5\right)_2\)
- B \(\mathrm{C}_6 \mathrm{H}_5-\mathrm{CO}_{-} \mathrm{CH}_3+\mathrm{I}_2+\mathrm{Na}_2 \mathrm{CO}_3(\mathrm{Heat}) \rightarrow \mathrm{CHI}_3+\mathrm{C}_6 \mathrm{H}_5 \mathrm{COO}^{-}\)
- C \(\mathrm{CH}_3-\mathrm{CO}-\mathrm{CH}_3+\mathrm{NH}_2-\mathrm{NH}-\mathrm{CO}-\mathrm{NH}_2(\) weakly basic \() \rightarrow\left(\mathrm{CH}_3\right)_2 \mathrm{C}=\mathrm{N}-\mathrm{NH}-\mathrm{CO}-\mathrm{NH}_2\)
- D \(\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CN} \xrightarrow[\text { (ii). } \mathrm{H}_2 \mathrm{O}]{\text { (i). DIBAL - } \mathrm{H}} \mathrm{CH}_3-\left(\mathrm{CH}_2\right)_4-\mathrm{CHO}\)
Answer & Solution
Correct Answer
(D) \(\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CN} \xrightarrow[\text { (ii). } \mathrm{H}_2 \mathrm{O}]{\text { (i). DIBAL - } \mathrm{H}} \mathrm{CH}_3-\left(\mathrm{CH}_2\right)_4-\mathrm{CHO}\)
Step-by-step Solution
Detailed explanation
Option (8BNT6): Acetaldehyde reacts with ethanol in the presence of dry HCl gas to form an acetal, \(\mathrm{CH}_3\mathrm{CH}(\mathrm{OC}_2\mathrm{H}_5)_2\). This is a correct reaction. Option (kuGqc): Acetophenone contains a methyl ketone group, which undergoes the iodoform…
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