COMEDK · Chemistry · 4. Chemical Bonding and Molecular Structure
Which of these represents the correct order of their increasing bond order?
- A \(\mathrm{C}_{2}^{2-} < \mathrm{He}_{2}^{+} < \mathrm{O}_{2}^{+} < \mathrm{O}_{2}^{-}\)
- B \(\mathrm{He}_{2}^{+} < \mathrm{O}_{2}^{-} < \mathrm{O}_{2}^{+} < \mathrm{C}_{2}^{2-}\)
- C \(\mathrm{O}_{2}^{-} < \mathrm{O}_{2}^{+} < \mathrm{C}_{2}^{2-} < \mathrm{He}_{2}^{+}\)
- D \(\mathrm{O}_{2}^{+} < \mathrm{C}_{2}^{2-} < \mathrm{O}_{2}^{-} < \mathrm{He}_{2}^{+}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{He}_{2}^{+} < \mathrm{O}_{2}^{-} < \mathrm{O}_{2}^{+} < \mathrm{C}_{2}^{2-}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{He}_{2}^{+}=\sigma 1 s^{2}, \sigma^{*} 1 s^{1}\) Bond order \(=\frac{1}{2}\left(N_{b}-N_{a}\right)\) \(N_{b}\) is number of bonding electrons \(N_{a}\) is number of anti-bonding electrons…
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