COMEDK · Chemistry · 4. Chemical Bonding and Molecular Structure
Which of these represents the correct order of decreasing bond order?
- A \(\mathrm{C}_2^{2-}>\mathrm{O}_2^{2+}>\mathrm{O}_2^{-}>\mathrm{He}_2^{2+}\)
- B \(\mathrm{O}_2^{-}>\mathrm{O}_2^{+}>\mathrm{He}_2^{+}>\mathrm{C}_2^{2-}\)
- C \(\mathrm{He}_2^{+}>\mathrm{O}_2^{-}>\mathrm{C}_2^{2-}>\mathrm{O}_2^{+}\)
- D \(\mathrm{He}_2^{+}>\mathrm{O}_2^{2-}>\mathrm{O}_2^{+}>\mathrm{O}_2^{-}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{C}_2^{2-}>\mathrm{O}_2^{2+}>\mathrm{O}_2^{-}>\mathrm{He}_2^{2+}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \mathrm{He}_2^{+}: \sigma 1 s^2, \sigma 1 s^1 \\ & \mathrm{BO}=\frac{1}{2}\left(N_b-N_a\right)=\frac{1}{2}(2-1)=\frac{1}{2}=0.5 \\ & \mathrm{C}_2^{2-}: \sigma 1 s^2, \sigma^* 1 s^2, \sigma 2 s^2, \sigma^* 2 s^2,\left(\pi 2 p_x^2 \approx \pi 2 p_y^2\right),…
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