COMEDK · Chemistry · 28. Carboxylic Acid Derivatives
Which of the following is the correct sequence of relative acidic strength?
- A \(\mathrm{FCH}_{2} \mathrm{COOH}>\mathrm{ClCH}_{2} \mathrm{COOH}>\mathrm{BrCH}_{2} \mathrm{COOH}\)
- B \(\mathrm{ClCH}_{2} \mathrm{COOH}>\mathrm{BrCH}_{2} \mathrm{COOH}>\mathrm{FCH}_{2} \mathrm{COOH}\)
- C \(\mathrm{BrCH}_{2} \mathrm{COOH}>\mathrm{ClCH}_{2} \mathrm{COOH}>\mathrm{FCH}_{2} \mathrm{COOH}\)
- D \(\mathrm{ClCH}_{2} \mathrm{COOH}>\mathrm{FCH}_{2} \mathrm{COOH}>\mathrm{BrCH}_{2} \mathrm{COOH}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{FCH}_{2} \mathrm{COOH}>\mathrm{ClCH}_{2} \mathrm{COOH}>\mathrm{BrCH}_{2} \mathrm{COOH}\)
Step-by-step Solution
Detailed explanation
Acid strength increases as the electronegativity of halogen increases because the anion formed after \(\mathrm{H}^{+}\) ion release, is stabilised by \(-I\)-effect. The order of \(-\mathrm{I}\)-effect is \(\mathrm{F}>\mathrm{Cl}>\mathrm{Br}>\mathrm{I}\). \(\therefore\) Order of…
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