COMEDK · Chemistry · 17. Solutions
Which of the following is correct order of their increasing boiling points?
- A \(10^{-4} \mathrm{M} \mathrm{NaCl}>10^{-3} \mathrm{M} \mathrm{MgCl}_{2}>10^{-2} \mathrm{M} \mathrm{NaCl}\) \(>10^{-4} \mathrm{M}\) urea.
- B \(10^{-2} \mathrm{M} \mathrm{NaCl}>10^{-3} \mathrm{M} \mathrm{MgCl}_{2}>10^{-4} \mathrm{M} \mathrm{NaCl}\) \(>10^{-4} \mathrm{M}\) urea.
- C \(10^{-4} \mathrm{M}\) urea \(>10^{-4} \mathrm{M} \mathrm{NaCl}>10^{-3} \mathrm{M} \mathrm{MgCl}_{2}\) \(>10^{-2} \mathrm{M} \mathrm{NaCl}\).
- D \(10^{-2} \mathrm{M} \mathrm{NaCl}>10^{-3} \mathrm{M} \mathrm{MgCl}_{2}>10^{-4} \mathrm{M} \mathrm{NaCl}\) \(>10^{-4} \mathrm{M}\) urea.
Answer & Solution
Correct Answer
(B) \(10^{-2} \mathrm{M} \mathrm{NaCl}>10^{-3} \mathrm{M} \mathrm{MgCl}_{2}>10^{-4} \mathrm{M} \mathrm{NaCl}\) \(>10^{-4} \mathrm{M}\) urea.
Step-by-step Solution
Detailed explanation
The elevation in boiling point is given by \(\Delta T_b = i \times K_b \times m\), where \(i\) is the van't Hoff factor and \(m\) is the molality. Since \(K_b\) is constant for the solvent, the boiling point is directly proportional to the product \(i \times m\). Calculate the…
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