COMEDK · Chemistry · 23. d and f Block Elements
Which is the correct order of increasing number of unpaired electrons in the following ions?
\(\mathrm{A}=\mathrm{Cr}^{2+}(\mathrm{Z}=24) \mathrm{B}=\mathrm{Cu}^{2+}(\mathrm{Z}=29) \quad \mathrm{C}=\mathrm{Ni}^{2+}(\mathrm{Z}=28) \mathrm{D}=\mathrm{Fe}^{3+}(\mathrm{Z}=26)\)
- A \(\mathrm{B} <\mathrm{C} <\mathrm{A} <\mathrm{D}\)
- B \(\mathrm{D} <\mathrm{C} <\mathrm{A} <\mathrm{B}\)
- C \(\mathrm{C} <\mathrm{B} <\mathrm{D} <\mathrm{A}\)
- D \(\mathrm{B} <\mathrm{C} <\mathrm{D} <\mathrm{A}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{B} <\mathrm{C} <\mathrm{A} <\mathrm{D}\)
Step-by-step Solution
Detailed explanation
The electronic configuration of the neutral atoms and their respective ions are determined as follows: For \(\mathrm{Cr}^{2+}\) (\(Z=24\)): The neutral configuration is \([Ar] 3d^{5} 4s^{1}\). Removing two electrons gives \([Ar] 3d^{4}\). The number of unpaired electrons is…
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