COMEDK · Chemistry · 18. Electrochemistry
When the same amount of electricity is passed through solutions of silver nitrate and copper sulphate, \(0.4 \mathrm{~g}\) copper is deposite(d)The amount of silver deposited is
- A \(1.35 \mathrm{~g}\)
- B \(2.7 \mathrm{~g}\)
- C \(5.1 \mathrm{~g}\)
- D \(5.4 \mathrm{~g}\)
Answer & Solution
Correct Answer
(A) \(1.35 \mathrm{~g}\)
Step-by-step Solution
Detailed explanation
According to Faraday's second law, \[ \frac{w_{1}}{E_{1}}=\frac{w_{2}}{E_{2}} \] where, \(w\) and \(E\) are mass and equivalent weight respectively. \(\frac{0.4}{\frac{63.5}{2}}=\frac{w_{2}}{108}\) \(\therefore \quad w_{2}=1.35 \mathrm{~g}\)
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