COMEDK · Chemistry · 6. Thermodynamics (C)
When \(50 \mathrm{~cm}^{3}\) of \(0.2 \mathrm{NH}_{2} \mathrm{SO}_{4}\) is mixed with \(50 \mathrm{~cm}^{3}\) of \(1 \mathrm{~N} \mathrm{KOH}\), the heat liberated is
- A \(573 \mathrm{~kJ}\)
- B \(573 \mathrm{~J}\)
- C \(11.46 \mathrm{~kJ}\)
- D \(57.3 \mathrm{~kJ}\)
Answer & Solution
Correct Answer
(B) \(573 \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
Equivalent moles of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) and \(\mathrm{KOH}\) undergoing neutralisation \(=50 \times 0.2 \times 10^{-3}=0.01\) \(\therefore\) Heat of neutralisation \(=0.01 \times 57.3 \mathrm{~kJ}=573 \mathrm{~J}\)
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