COMEDK · Chemistry · 18. Electrochemistry
When \(0.1 \mathrm{~mol} \mathrm{~L}^{-1}\) of KCl was filled in a Conductivity cell the resistance was 80 ohms at 298 K . (Conductivity of 0.1 M KCl at 298 K is \(1.29 \mathrm{~S} \mathrm{~m}^{-1}\). The same cell when filled with an unknown electrolyte of concentration 0.025 M , had a resistance of 92 ohms. What is the Molar conductivity of the electrolyte at the given concentration?
- A \(448.7 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\)
- B \(220.6 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\)
- C \(0.449 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\)
- D \(0.2206 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\)
Answer & Solution
Correct Answer
(A) \(448.7 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\)
Step-by-step Solution
Detailed explanation
The cell constant \(G^{*}\) is given by the product of conductivity \(\kappa\) and resistance \(R\). For the KCl solution, \(\kappa_{KCl} = 1.29 \text{ S m}^{-1} = 1.29 \times 10^{-2} \text{ S cm}^{-1}\).…
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