COMEDK · Chemistry · 18. Electrochemistry
What would be the EMF of the cell in which the following reaction occurs:
\(\begin{aligned}
& \mathrm{Cd}(\mathrm{S})+2 \mathrm{H}^{+} \rightarrow \mathrm{Cd}^{2+}+\mathrm{H}_{2(\mathrm{~g})} \\
& {\left[\mathrm{H}^{+}\right]=0.02 \mathrm{M} \quad \mathrm{E}^0\left(\mathrm{Cd}^{2+} / \mathrm{Cd}\right)=-0.4 \mathrm{~V},\left[\mathrm{Cd}^{2+}\right]=0.01 \mathrm{M} \text { and partial pressure of } \mathrm{H}_2 \text { gas }=0.8 \mathrm{~atm} .}
\end{aligned}\)
- A 0.4859 V
- B 0.4471 V
- C 0.3020 V
- D 0.3616 V
Answer & Solution
Correct Answer
(D) 0.3616 V
Step-by-step Solution
Detailed explanation
The cell reaction is \(\mathrm{Cd}(s) + 2\mathrm{H}^{+}(aq) \rightarrow \mathrm{Cd}^{2+}(aq) + \mathrm{H}_{2}(g)\). The standard cell potential \(E^{0}_{cell}\) is calculated as \(E^{0}_{cathode} - E^{0}_{anode}\). Given \(E^{0}(\mathrm{H}^{+}/\mathrm{H}_{2}) = 0.00 \text{ V}\)…
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