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COMEDK · Chemistry · 18. Electrochemistry

What will be the change in the electrode potential of chromium electrode dipping into chromic sulphate solution, when the electrolyte is diluted 10 times at \(25^\circ\)C? [ \(E^0\ (\text{Cr}^{3+}/\text{Cr})] = -0.74\)V

  1. A Decrease by 29.6 mV
  2. B Increase by 16.2 mV
  3. C Increase by 32.8 mV
  4. D Decrease by 19.7 mV
Verified Solution

Answer & Solution

Correct Answer

(D) Decrease by 19.7 mV

Step-by-step Solution

Detailed explanation

The reduction half-reaction for the chromium electrode is: \(\text{Cr}^{3+} + 3e^- \rightarrow \text{Cr}\) The Nernst equation for the reduction potential is given by: \(E = E^0 - \dfrac{0.0591}{n} \log \dfrac{1}{[\text{Cr}^{3+}]}\)…