COMEDK · Chemistry · 17. Solutions
What is the percentage dissociation of 0.8ml of Acetic acid (density is 1.04g/ml) which is dissolved in 1.2L of water if the observed Depression in freezing point is 0.0228 K? (\(K_f\) for water = 1.86Kkg/mol.)
- A \(9\)
- B \(6\)
- C \(10\)
- D \(12\)
Answer & Solution
Correct Answer
(B) \(6\)
Step-by-step Solution
Detailed explanation
Mass of acetic acid \(= \text{Volume} \times \text{Density} = 0.8 \times 1.04 = 0.832 \text{ g}\) Molar mass of acetic acid (\(\text{CH}_3\text{COOH}\)) \(= 60 \text{ g/mol}\) Number of moles of acetic acid \(= \dfrac{0.832}{60} = 0.01387 \text{ mol}\) Mass of water…
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