COMEDK · Chemistry · 17. Solutions
Two volatile liquids X and Y form an ideal solution at 298 K and have vapour pressures equal to 100 mm and 200 mm of Hg respectively in their pure state. The mole fraction of X in the solution is 0.4 and the mole fraction of Y in the vapour phase is a/20. Calculate the value of a.
- A \(5\)
- B \(25\)
- C \(10\)
- D \(15\)
Answer & Solution
Correct Answer
(D) \(15\)
Step-by-step Solution
Detailed explanation
Given the pure vapour pressures \(P^{\circ}_{X} = 100\) mm Hg and \(P^{\circ}_{Y} = 200\) mm Hg. The mole fraction of X in the liquid phase is \(x_{X} = 0.4\). Therefore, the mole fraction of Y in the liquid phase is \(x_{Y} = 1 - 0.4 = 0.6\). Using Raoult's Law, the partial…
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