COMEDK · Chemistry · 17. Solutions
Two liquids A and B form an ideal solution. At 300 K , the vapour pressure of pure A and pure B are \(8 \times 10^3 \mathrm{~Pa}\) and \(12 \times 10^3 \mathrm{~Pa}\) respectively. If the solution has 40 mole percent of \(A\), the composition of \(A\) and \(B\) in the vapour phase is:
- A 0.30 and 0.70
- B 0.40 and 0.60
- C 0.76 and 0.24
- D 0.28 and 0.72
Answer & Solution
Correct Answer
(A) 0.30 and 0.70
Step-by-step Solution
Detailed explanation
Given the mole fraction of A in the liquid phase \(x_A = 0.40\). Since the solution is ideal, the mole fraction of B in the liquid phase is \(x_B = 1 - x_A = 1 - 0.40 = 0.60\). The vapour pressures of pure components are \(P_A^{0} = 8 \times 10^3 \text{ Pa}\) and…
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