COMEDK · Chemistry · 16. Solid State
Two ions \(A^{+}\)and \(B^{-}\)have radii 104 and 200 pm respectively, in a cubic close packed crystal of compound \(A B\). The coordination number of \(A^{+}\) is
- A 4
- B 8
- C 6
- D 3
Answer & Solution
Correct Answer
(C) 6
Step-by-step Solution
Detailed explanation
\(r_{A^{+}}^{+}=104 \mathrm{pm}\) \(r_{B^{-}}^{-}=200 \mathrm{pm}\) Radius ratio \(\frac{r_{A^{+}}^{+}}{r_{B^{-}}^{-}}=\frac{104}{200}=0.52\) \(\because\) It lies between \((0.414\) to \(0.732) .\) \(\therefore\) Coordination number of \(A^{+}\)is 6
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