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COMEDK · Chemistry · 24. Coordination Compounds

\(\mathrm{Ti}^{2+}\) is purple while \(\mathrm{Ti}^{4+}\) is colourless because

  1. A \(\mathrm{Ti}^{2+}\) has \(3 d^2\) configuration
  2. B \(\mathrm{Ti}^{4+}\) has \(3 d^2\) configuration
  3. C \(\mathrm{Ti}^{2+}\) is very small cation when compared to \(\mathrm{Ti}^{2+}\) and hence, doesn't absorb any radiation
  4. D There is no crystal field effect in \(\mathrm{Ti}^{4+}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\mathrm{Ti}^{2+}\) has \(3 d^2\) configuration

Step-by-step Solution

Detailed explanation

\(\begin{aligned} \mathrm{Ti}^{2+} & =[\mathrm{Ar}] 3 d^2 \\ \mathrm{Ti}^{4+} & =[\mathrm{Ar}] 3 d^0 \end{aligned}\) \(\mathrm{Ti}^{2+}\) has two unpaired electrons in \(3 d\) orbital and hence \(d-d\) transition is possible due to absorption of light in visible region whereas…