COMEDK · Chemistry · 24. Coordination Compounds
\(\mathrm{Ti}^{2+}\) is purple while \(\mathrm{Ti}^{4+}\) is colourless because
- A \(\mathrm{Ti}^{2+}\) has \(3 d^2\) configuration
- B \(\mathrm{Ti}^{4+}\) has \(3 d^2\) configuration
- C \(\mathrm{Ti}^{2+}\) is very small cation when compared to \(\mathrm{Ti}^{2+}\) and hence, doesn't absorb any radiation
- D There is no crystal field effect in \(\mathrm{Ti}^{4+}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{Ti}^{2+}\) has \(3 d^2\) configuration
Step-by-step Solution
Detailed explanation
\(\begin{aligned} \mathrm{Ti}^{2+} & =[\mathrm{Ar}] 3 d^2 \\ \mathrm{Ti}^{4+} & =[\mathrm{Ar}] 3 d^0 \end{aligned}\) \(\mathrm{Ti}^{2+}\) has two unpaired electrons in \(3 d\) orbital and hence \(d-d\) transition is possible due to absorption of light in visible region whereas…
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