COMEDK · Chemistry · 23. d and f Block Elements

\(\mathrm{Ti}^{2+}\) is purple while \(\mathrm{Ti}^{4+}\) is colourless because

A There is no crystal field effect in \(\mathrm{Ti}^{4+}\)
B \(\mathrm{Ti}^{4+}\) has \(3 d^2\) configuration
C \(\mathrm{Ti}^{2+}\) has \(3 d^2\) configuration
D \(\mathrm{Ti}^{2+}\) is very small cation when compared to \(\mathrm{Ti}^{2+}\) and hence, doesn't absorb any radiation

Verified Solution

Answer & Solution

Correct Answer

(C) \(\mathrm{Ti}^{2+}\) has \(3 d^2\) configuration

Step-by-step Solution

Detailed explanation

The electronic configuration of titanium is \([Ar] 3d^2 4s^2\). For \(\mathrm{Ti}^{2+}\), the configuration is \([Ar] 3d^2\). Since there are two electrons in the \(d\)-orbitals, \(d-d\) transitions are possible when light is absorbed, resulting in the purple color. For…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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