COMEDK · Chemistry · 24. Coordination Compounds
The wavelength absorbed by the complex \([Cu(H_2O)_4]^{2+}\) (assuming tetrahedral geometry) for the d-d transition is 600 nm. The crystal field splitting energy for the complex \([Cu(H_2O)_6]^{2+}\) is:
[Given: \(h = 6.626 \times 10^{-34}\text{ Js}\), \(c = 3 \times 10^8\text{ ms}^{-1}\), and \(1\text{ eV} = 1.6 \times 10^{-19}\text{ J}\)]
- A 3.6 eV
- B 4.7 eV
- C 3.9 eV
- D 5.2 eV
Answer & Solution
Correct Answer
(B) 4.7 eV
Step-by-step Solution
Detailed explanation
Tetrahedral splitting energy: \(\Delta_t = \dfrac{hc}{\lambda} = \dfrac{(6.626 \times 10^{-34})(3 \times 10^8)}{600 \times 10^{-9}} = 3.313 \times 10^{-19}\) J Since \(\Delta_t = \dfrac{4}{9}\Delta_o\):…
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