COMEDK · Chemistry · 18. Electrochemistry
The volume of \(\mathrm{H}_{2}\) obtained at \(\mathrm{STP}\), when \(\mathrm{Mg}\) obtained by passing a current of \(0.5 \mathrm{~A}\) through molten \(\mathrm{MgCl}_{2}\) for \(32.2\) min is treated with excess of dilute HCl is approximately
[Equivalent mass of \(\mathrm{Mg}=12\) ]
- A \(56 \mathrm{~cm}^{3}\)
- B \(28 \mathrm{~cm}^{3}\)
- C \(5.6 \mathrm{~cm}^{3}\)
- D \(112 \mathrm{~cm}^{3}\)
Answer & Solution
Correct Answer
(D) \(112 \mathrm{~cm}^{3}\)
Step-by-step Solution
Detailed explanation
\(I=0.5 \mathrm{~A}\)…
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