COMEDK · Chemistry · 8. Ionic Equilibrium
The volume of \(10 \mathrm{~N}\) and \(4 \mathrm{~N}\) HCl required to make 1 litre of \(7 \mathrm{~N} \mathrm{HCl}\) are
- A \(0.75\) litre of \(10 \mathrm{~N} \mathrm{HCl}\) and \(0.25\) litre of \(4 \mathrm{~N} \mathrm{HCl}\)
- B \(0.80\) litre of \(10 \mathrm{~N} \mathrm{HCl}\) and \(0.20\) litre of \(4 \mathrm{~N} \mathrm{HCl}\)
- C \(0.60\) litre of \(10 \mathrm{~N} \mathrm{HCl}\) and \(0.40\) litre of \(4 \mathrm{~N} \mathrm{HCl}\)
- D \(0.50\) litre of \(10 \mathrm{~N} \mathrm{HCl}\) and \(0.50\) litre of \(4 \mathrm{~N} \mathrm{HCl}\)
Answer & Solution
Correct Answer
(D) \(0.50\) litre of \(10 \mathrm{~N} \mathrm{HCl}\) and \(0.50\) litre of \(4 \mathrm{~N} \mathrm{HCl}\)
Step-by-step Solution
Detailed explanation
I et the volume of \(10 \mathrm{~N} \mathrm{HCl}\) used is \(x\) litre.- \(\therefore\) The volume of \(4 \mathrm{~N} \mathrm{HCl}\) used is \((1-x)\) litre.…
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