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COMEDK · Chemistry · 18. Electrochemistry

The reaction taking place in a galvanic cell is as given
\(\mathrm{A}(\mathrm{s})+\mathrm{B}^{2+}\left(\mathrm{1} \mathrm{1} \mathrm{1 0} \mathrm{0}^{-\mathrm{M}} \mathrm{M}\right) \rightarrow \mathrm{B}_{(\mathrm{s})}+\mathrm{A}^{2+}(0.1 \mathrm{M}).\)
The emf of the cell is \(+2.651 \mathrm{~V}\). If the standard emf of the cell is \(+2.71 \mathrm{~V}\), what is the value of \(\mathrm{X}\) ?

  1. A X = 2
  2. B X = 3
  3. C X = 4
  4. D X = 6
Verified Solution

Answer & Solution

Correct Answer

(B) X = 3

Step-by-step Solution

Detailed explanation

The cell reaction is \(\mathrm{A}(\mathrm{s}) + \mathrm{B}^{2+}(10^{-X} \mathrm{M}) \rightarrow \mathrm{B}(\mathrm{s}) + \mathrm{A}^{2+}(0.1 \mathrm{M})\). The Nernst equation for the cell at \(298 \mathrm{K}\) is given by…