COMEDK · Chemistry · 19. Chemical Kinetics

The rate constant for a zero order reaction \(\mathrm{A} \rightarrow \mathrm{B}+\mathrm{C}\) is \(6.0 \times 10^{-3} \mathrm{molL}^{-1} \mathrm{~s}^{-1}\).
What would be the time taken for the initial concentration of A to decrease from 0.2 M to 0.024 M ?

A 37.34 s
B 29.33 s
C 15.83 s
D 31.90 s

Verified Solution

Answer & Solution

Correct Answer

(B) 29.33 s

Step-by-step Solution

Detailed explanation

For a zero order reaction, the integrated rate equation is given by \([A]_t = [A]_0 - kt\), where \([A]_0\) is the initial concentration, \([A]_t\) is the concentration at time \(t\), and \(k\) is the rate constant. Given values are \([A]_0 = 0.2 \text{ M}\),…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Characteristics	Vitamins
A	Water soluble that is not excreted easily	W	B\(_2\)
B	Prevents Cheilosis	X	B\(_6\)
C	Fat soluble	Y	B\(_{12}\)
D	Prevents seizures and convulsions	Z	E

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The rate constant for a zero order reaction \(\mathrm{A} \rightarrow \mathrm{B}+\mathrm{C}\) is \(6.0 \times 10^{-3} \mathrm{molL}^{-1} \mathrm{~s}^{-1}\).What would be the time taken for the initial concentration of A to decrease from 0.2 M to 0.024 M ?

Step-by-step Solution

The rate constant for a zero order reaction \(\mathrm{A} \rightarrow \mathrm{B}+\mathrm{C}\) is \(6.0 \times 10^{-3} \mathrm{molL}^{-1} \mathrm{~s}^{-1}\).
What would be the time taken for the initial concentration of A to decrease from 0.2 M to 0.024 M ?